document.write( "Question 124817: Hi. I need some help with the following problem. Thanks\r
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document.write( "Use the given information to find the constant of proportionality.
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document.write( "S varies jointly as p and q. If p = 3 and q = 7, then S = -21.\r
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document.write( "k = \n" );
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Algebra.Com's Answer #91606 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Saying that S varies jointly as p and q means that S is related to the product of p and q as in: \n" ); document.write( ". \n" ); document.write( "S = k*p*q \n" ); document.write( ". \n" ); document.write( "in which k represents the constant of proportionality. \n" ); document.write( ". \n" ); document.write( "You are given that when p = 3 and q = 7, then S = -21. You can use these values to find the \n" ); document.write( "value of k. Substitute 3 for p and 7 for q and -21 for S to get: \n" ); document.write( ". \n" ); document.write( "-21 = k*3*7 \n" ); document.write( ". \n" ); document.write( "Multiply out the right side to get: \n" ); document.write( ". \n" ); document.write( "-21 = k*21 \n" ); document.write( ". \n" ); document.write( "Divide both sides by 21 ... the multiplier of k ... to get: \n" ); document.write( ". \n" ); document.write( "-21/21 = k \n" ); document.write( ". \n" ); document.write( "This simplifies to \n" ); document.write( ". \n" ); document.write( "k = -1 \n" ); document.write( ". \n" ); document.write( "Now return to the original joint variation equation of: \n" ); document.write( ". \n" ); document.write( "S = k*p*q \n" ); document.write( ". \n" ); document.write( "substitute -1 for k and you have the joint variation equation as being: \n" ); document.write( ". \n" ); document.write( "S = -1*p*q = -pq \n" ); document.write( ". \n" ); document.write( "So that is the answer to this problem ... k = -1 and as additional information you have the \n" ); document.write( "additional knowledge that the equation for S is S = -pq \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem. \n" ); document.write( " \n" ); document.write( " |