document.write( "Question 124946: Mixing 100% antifreeze with 40% antifreeze to get 20 quarts of 50% antifreeze \n" ); document.write( "
Algebra.Com's Answer #91591 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X+.4(20-X)=.5*20 \n" ); document.write( "X+8-.4X=10 \n" ); document.write( ".6X=10-8 \n" ); document.write( ".6X=2 \n" ); document.write( "X=2/.6 \n" ); document.write( "X=3.333 QTS OF PURE ANTIFREEZE IS NEEDED TO GET A 50% MIX. \n" ); document.write( "PROOF \n" ); document.write( "3.333+.4(20-3.333)=.5*20 \n" ); document.write( "3.333+.4*16.667=10 \n" ); document.write( "3.333+6.667=0 \n" ); document.write( "10=10 \n" ); document.write( " \n" ); document.write( " |