document.write( "Question 124946: Mixing 100% antifreeze with 40% antifreeze to get 20 quarts of 50% antifreeze \n" ); document.write( "
Algebra.Com's Answer #91591 by checkley71(8403)\"\" \"About 
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X+.4(20-X)=.5*20
\n" ); document.write( "X+8-.4X=10
\n" ); document.write( ".6X=10-8
\n" ); document.write( ".6X=2
\n" ); document.write( "X=2/.6
\n" ); document.write( "X=3.333 QTS OF PURE ANTIFREEZE IS NEEDED TO GET A 50% MIX.
\n" ); document.write( "PROOF
\n" ); document.write( "3.333+.4(20-3.333)=.5*20
\n" ); document.write( "3.333+.4*16.667=10
\n" ); document.write( "3.333+6.667=0
\n" ); document.write( "10=10
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