document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124940>Question 124940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number exceeds three times a second number by 7. The sum of twice the larger number and four times the smaller nu<BR>\n" );
document.write( "mber is 44. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91586 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the numbers be x & y.\r<BR>\n" );
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document.write( "According to the data given we write \"x\" in terms of \"y\". \r<BR>\n" );
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document.write( "x = 3y + 7 \r<BR>\n" );
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document.write( "Given that: \r<BR>\n" );
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document.write( "2(3y + 7) + 4y = 44\r<BR>\n" );
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document.write( "6y + 14 + 4y = 44\r<BR>\n" );
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document.write( "10y = 44 - 14\r<BR>\n" );
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document.write( "10y = 30 \r<BR>\n" );
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document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30%2F10 ALIGN=MIDDLE  ALT=\"30%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "y = 3\r<BR>\n" );
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document.write( "By back substitution, we get: \r<BR>\n" );
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document.write( "x = 3(y) + 7 \r<BR>\n" );
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document.write( "x = 3(3) + 7 \r<BR>\n" );
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document.write( "x = 9 + 7 \r<BR>\n" );
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document.write( "x = 16 \r<BR>\n" );
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document.write( "Thus the values are x = 16 & y = 3\r<BR>\n" );
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document.write( "Hence, the solution. </SPAN>\n" );
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