document.write( "Question 124851: 1. Pat invested a total of $3000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year. If the total yearly interest from this investment is $256, how much did Pat invest at 10 percent and how much at 8 percent?\r
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Algebra.Com's Answer #91580 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
let x=\"amount @ 10%\", so 3000-x=\"amount @ 8%\"\r
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\n" ); document.write( "\n" ); document.write( "(.10)(x)+(.08)(3000-x)=256 __ .1x+240-.08x=256 __ .02x=16
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