document.write( "Question 124943: How would you solve this equation?\r
\n" ); document.write( "\n" ); document.write( "a^2-3=2a
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Algebra.Com's Answer #91576 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"a%5E2-3=2a\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-3-2a=0\" Subtract 2a from both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-2a-3=0\" Rearrange the terms\r
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\n" ); document.write( "\n" ); document.write( "\"%28a-3%29%28a%2B1%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"a-3=0\" or \"a%2B1=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"a=3\" or \"a=-1\" Now solve for a in each case\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \r
\n" ); document.write( "\n" ); document.write( " \"a=3\" or \"a=-1\" \r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=x%5E2-2x-3\" (just replace a with x) we can see that the roots are \"x=3\" and \"x=-1\" . So this visually verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+x%5E2-2x-3%29+\"
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