document.write( "Question 124904: the larger of two numbers is five times the smaller. if the difference is fifty-two, what are these numbers? thanks for helping out. \n" ); document.write( "
Algebra.Com's Answer #91574 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Let L represent the larger number and S represent the smaller number. \n" ); document.write( ". \n" ); document.write( "The problem first tells you that the Larger number is 5 times the Smaller number. In equation \n" ); document.write( "form this becomes: \n" ); document.write( ". \n" ); document.write( "L = 5*S \n" ); document.write( ". \n" ); document.write( "Then the problem tells you that the difference of the two numbers is 52. In equation form \n" ); document.write( "this is: \n" ); document.write( ". \n" ); document.write( "L - S = 52 \n" ); document.write( ". \n" ); document.write( "But from the first equation you know that L equals 5S. So in the second equation you can \n" ); document.write( "substitute 5S for L. When you do that substitution the second equation becomes: \n" ); document.write( ". \n" ); document.write( "5S - S = 52 \n" ); document.write( ". \n" ); document.write( "Combine the two terms on the left side and the equation is reduced to: \n" ); document.write( ". \n" ); document.write( "4S = 52 \n" ); document.write( ". \n" ); document.write( "Solve for S by dividing both sides of this reduced equation by 4 and you get: \n" ); document.write( ". \n" ); document.write( "S = 52/4 = 13 \n" ); document.write( ". \n" ); document.write( "So now you know that the Smaller number is 13. And you also know that the Larger number is \n" ); document.write( "5 times the Smaller number. Therefore, the larger number is 5*13 = 65 \n" ); document.write( ". \n" ); document.write( "So now you know that the two numbers are 65 and 13. Notice that the difference in these \n" ); document.write( "two numbers is 52, just as the problem said it should be. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem a little better. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |