document.write( "Question 124840: x=1-y
\n" ); document.write( "y=2x-2\r
\n" ); document.write( "\n" ); document.write( "Please show me how to solve this problem. I keep getting stuck at x=1-(2x-2), and can't figure out where to go from here.Thank's for your help.
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Algebra.Com's Answer #91548 by iluvbuilding429(41)\"\" \"About 
You can put this solution on YOUR website!
x=1-y
\n" ); document.write( "y=2x-2\r
\n" ); document.write( "\n" ); document.write( "Please show me how to solve this problem. I keep getting stuck at x=1-(2x-2), and can't figure out where to go from here.Thank's for your help.

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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+1%2C%0D%0A++++-2%5Cx+%2B+1%5Cy+=+-2+%29%0D%0A++\"We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " \"1%2Ax+=+1+-+1%2Ay\", or \"x+=+1%2F1+-+1%2Ay%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"-2%2A%281%2F1+-+1%2Ay%2F1%29+%2B+1%5Cy+=+-2\" and simplify: So, we know that y=0. Since \"x+=+1%2F1+-+1%2Ay%2F1\", x=1.
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\n" ); document.write( " Answer: \"system%28+x=1%2C+y=0+%29\".
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