document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124899>Question 124899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x punds of candy valued at $3.50 per pound is mixed with y pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find x and y, the number of pounds of each type. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91534 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.50X+4.30(10-X)=4*10<BR>\n" );
document.write( "3.5X+43-4.3X=40<BR>\n" );
document.write( "-.8X=40-43<BR>\n" );
document.write( "-.8X=-3<BR>\n" );
document.write( "X=-3/-.8<BR>\n" );
document.write( "X=3.75 POUNDS OF $3.50 CANDY IS NEEDED.<BR>\n" );
document.write( "10-3.75=6.25 POUNDS OF $4.30 CANDY IS NEEDED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "3.50*3.75+4.30*6.25=4*10<BR>\n" );
document.write( "13.125+26.875=40<BR>\n" );
document.write( "40=40 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );