document.write( "Question 124890:
\n" ); document.write( "there are four numbers. the first is twenty less the second, the third is one more than twice the first and the forth is four more than the third. we also know that the sum of the second equals the sum of the third and fourth numbers. find the numbers. \n" ); document.write( "
Algebra.Com's Answer #91524 by checkley71(8403)\"\" \"About 
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LET THE 3 NUMBERS BE W,X,Y,Z. WHERE:
\n" ); document.write( "W=X-20
\n" ); document.write( "X=Y+Z
\n" ); document.write( "Y=W+1
\n" ); document.write( "Z=Y+4
\n" ); document.write( "WHERE DO WE START TO ELIMINATE THESE UNKNOWNS?????
\n" ); document.write( "LETS START WITH THE W & X.
\n" ); document.write( "W=(Y+Z)-20 NOW REPLACE W BY(Y-1)
\n" ); document.write( "Y-1=Y+Z-20 NOW CANCEL OUT THE Y TERMS.
\n" ); document.write( "-1=Z-20 NOW REPLACE Z BY Y+4
\n" ); document.write( "-1=Y+4-20 NOW SOLVE FOR Y.
\n" ); document.write( "Y=-1-4+20
\n" ); document.write( "Y=15 ANSWER. NOW SOLVE FOR Z.
\n" ); document.write( "Z=15+4=19 ANSWER. NOW SOLVE FOR X.
\n" ); document.write( "X=15+19=34 ANSWER. NOW SOLVE FOR W.
\n" ); document.write( "W=34-20=14 ANSWER.
\n" ); document.write( "THUS WE HAVE:
\n" ); document.write( "W=14
\n" ); document.write( "X=34
\n" ); document.write( "Y=15
\n" ); document.write( "Z=19\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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