document.write( "Question 19024: -3x > 0 and 3x -4<11
\n" ); document.write( " can anyone solve this\r
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Algebra.Com's Answer #9152 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
1)
\n" ); document.write( " $\"-3x+%3E+0\"$ Divide both sides by -3...don't forget to reverse the order of the inequality when you divide by a negative.
\n" ); document.write( " $\"x+%3C+0\"$ \r
\n" ); document.write( "\n" ); document.write( "2)
\n" ); document.write( " $\"3x-4+%3C+11\"$ Add 4 to both sides.
\n" ); document.write( " $\"3x+%3C+15\"$ Divide both sides by 3.
\n" ); document.write( " $\"x+%3C+5\"$ \n" ); document.write( "

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