document.write( "Question 124730: Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned home 40 hours after leaving. How many miles is City A from City B \n" ); document.write( "
Algebra.Com's Answer #91509 by ankor@dixie-net.com(22740)\"\" \"About 
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Wilma drove at an average speed of 50 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 45 mi/h. She returned home 40 hours after leaving. How many miles is City A from City B
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\n" ); document.write( "First of all, let's just concern ourselves with the traveling time:
\n" ); document.write( "Subtract the 10 hr stay from the total time (40 hr) she was gone;
\n" ); document.write( "She had 30 hrs on the road
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\n" ); document.write( "Let d = distance from A to B
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\n" ); document.write( "Write a time equation: Time = \"distance%2Fspeed\"
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\n" ); document.write( "Time to B + time to A = 30 hrs
\n" ); document.write( "\"d%2F50\" + \"d%2F45\" = 30
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\n" ); document.write( "Multiply equation by a multiple of both denominators, 450 would do it:
\n" ); document.write( "450*\"d%2F50\" + 450*\"d%2F45\" = 450(30)
\n" ); document.write( "Cancel out the denominators and you have:
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\n" ); document.write( "9d + 10d = 13500
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\n" ); document.write( "19d = 13500
\n" ); document.write( "d = \"13500%2F19\"
\n" ); document.write( "d = 710.5 miles from A to B
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\n" ); document.write( "Check solution by finding the time each way and finding the total time:
\n" ); document.write( "710.5/50 = 14.2 hrs
\n" ); document.write( "710.5/45 = 15.8 hrs
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\n" ); document.write( "Total time 30.0 hrs as given
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\n" ); document.write( "Did I make this understandable? Any questions?\r
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