document.write( "Question 124726: For a certain experiment, a student requires 300 ml of a solution that is 13% HCl (hydrochloric acid). The storeroom has only solutions that are 10% HCl and 15% HCl. How many milliliters of each available solution should be mixed to get 300 ml of 13% HCl? \r
\n" );
document.write( "\n" );
document.write( "Could you please explain to me how to solve this problem? \n" );
document.write( "
Algebra.Com's Answer #91504 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! For a certain experiment, a student requires 300 ml of a solution that is 13% HCl (hydrochloric acid). The storeroom has only solutions that are 10% HCl and 15% HCl. How many milliliters of each available solution should be mixed to get 300 ml of 13% HCl? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 15% HCL \n" ); document.write( "the total resulting amt must be 300 ml, therefore: \n" ); document.write( "(300-x) = amt of 10% HCL \n" ); document.write( ": \n" ); document.write( ".15x + .10(300-x) =.13(300) \n" ); document.write( ": \n" ); document.write( ".15x + 30 - .10x = 39 \n" ); document.write( ": \n" ); document.write( ".15x - .10x = 39 - 30 \n" ); document.write( ": \n" ); document.write( ".05x = 9 \n" ); document.write( "x = \n" ); document.write( "x = 180 ml of 15% HCL \n" ); document.write( "then \n" ); document.write( "300 - 180 = 120 ml of 10% HCL \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can check our solution in the original equation \n" ); document.write( ".15(180) + .10(120) = .13(300) \n" ); document.write( " 27 + 12 = 39 \n" ); document.write( ": \n" ); document.write( "Did this make sense to you? Any questions? \n" ); document.write( " \n" ); document.write( " |