document.write( "Question 124854: 30x+50y-100=0
\n" ); document.write( "3x-15y-30=0 \n" ); document.write( "
Algebra.Com's Answer #91498 by stanbon(75887)\"\" \"About 
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30x+50y-100=0
\n" ); document.write( "3x-15y-30=0
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\n" ); document.write( "Rearrange and divide to get:
\n" ); document.write( "3x + 5y = 10
\n" ); document.write( "x - 5y = 10
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\n" ); document.write( "x = 5y+10
\n" ); document.write( "Substitute to get:
\n" ); document.write( "3(5y+10) + 5y = 10
\n" ); document.write( "15y + 30 + 5y = 10
\n" ); document.write( "20y = -20
\n" ); document.write( "y = -1
\n" ); document.write( "----------
\n" ); document.write( "Substitute into x=5y+10
\n" ); document.write( "x = 5*-1+10 = 5
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\n" ); document.write( "Final answer: x= 5 ; y = -1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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