document.write( "Question 124825: Give answer in a + bi form.\r
\n" ); document.write( "\n" ); document.write( "4 - 5i / 2 + 3i
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Algebra.Com's Answer #91487 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
You need to remember the 'difference of two squares' factorization: \"%28a%2Bb%29%28a-b%29=a%5E2-b%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "What we want to accomplish is to get that pesky i out of our denominator. Using the difference of two squares idea, we see that we can accomplish this quite nicely by multiplying the denominator by \"2-3i\". Of course if we multiply the denominator by something, we must multiply the numerator by the same thing, so:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%284-5i%29%2F%282%2B3i%29%29%28%282-3i%29%2F%282-3i%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Using the difference of two squares on the denominator, and FOIL on the numerator we obtain:\r
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\n" ); document.write( "\n" ); document.write( "\"%288-12i-10i%2B15i%5E2%29%2F%284-9i%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Now, collect terms remembering that \"i%5E2=-1\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28-7%29-22i%29%2F13\"\r
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\n" ); document.write( "\n" ); document.write( "In \"a%2Bbi\" form you have: \"-%287%2F13%29-%2822%2F13%29i\"
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