document.write( "Question 124822: 5+X<2X+1<6-X\r
\n" ); document.write( "\n" ); document.write( "Can anyone help me understand how to solve this?
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Algebra.Com's Answer #91486 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"5%2BX%3C2X%2B1%3C6-X\"\r
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\n" ); document.write( "\n" ); document.write( "There are actually two relationships established here. Deal with each one separately.\r
\n" ); document.write( "\n" ); document.write( "\"5%2Bx%3C2x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Add -1 to each side.
\n" ); document.write( "\"4%2Bx%3C2x\"\r
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\n" ); document.write( "\n" ); document.write( "Add -x to each side.
\n" ); document.write( "\"4%3Cx\"\r
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\n" ); document.write( "\n" ); document.write( "Now look at the other relationship
\n" ); document.write( "\"2x%2B1%3C6-x\"\r
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\n" ); document.write( "\n" ); document.write( "Add -1 to each side
\n" ); document.write( "\"2x%3C5-x\"\r
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\n" ); document.write( "\n" ); document.write( "Add x to each side
\n" ); document.write( "\"3x%3C5\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by 3. (since we are dividing by a positive number, we keep the sense of the inequality as it is)
\n" ); document.write( "\"x%3C5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So, x must simultaneously be less than 5/3 and greater than 4. Impossible. There is no value of x that makes the original inequality a true statement.
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