document.write( "Question 124822: 5+X<2X+1<6-X\r
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document.write( "Can anyone help me understand how to solve this? \n" );
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Algebra.Com's Answer #91486 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are actually two relationships established here. Deal with each one separately.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add -1 to each side. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add -x to each side. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now look at the other relationship \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add -1 to each side \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add x to each side \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by 3. (since we are dividing by a positive number, we keep the sense of the inequality as it is) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, x must simultaneously be less than 5/3 and greater than 4. Impossible. There is no value of x that makes the original inequality a true statement. \n" ); document.write( " |