document.write( "Question 124607: I am working on solving linear and quadratic equations. I need help with this problem:\r
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document.write( "I believe the CD:(y-2)(3y-2)(3y+2)\r
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document.write( "Please help solve. Thanks.
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Algebra.Com's Answer #91485 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Assume you mean: \n" ); document.write( " \n" ); document.write( "Factor the denominators: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You're right about the common denominator, multiply each term by that: \n" ); document.write( "(y-2)(3y-2)(3y+2)* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators, leaving: \n" ); document.write( "(3y-2)(3y+1) + 9(y-2) = (3y+2)(2y-2) \n" ); document.write( ": \n" ); document.write( "FOIL \n" ); document.write( "(9y^2 - 3y - 2) + (9y-18) = 6y^2 - 2y - 4 \n" ); document.write( ": \n" ); document.write( "Combine like terms on the left \n" ); document.write( "9y^2 - 6y^2 - 3y + 9y + 2y - 2 - 18 + 4 = 0 \n" ); document.write( ": \n" ); document.write( "3y^2 + 8y - 16 = 0 \n" ); document.write( ": \n" ); document.write( "Factors to: \n" ); document.write( "(3y - 4)(y + 4) = 0 \n" ); document.write( ": \n" ); document.write( "3y = +4 \n" ); document.write( "y = \n" ); document.write( "and \n" ); document.write( "y = -4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "I checked the y=-4 solution in the original equation. \n" ); document.write( ": \n" ); document.write( "Did this help you? \n" ); document.write( " \n" ); document.write( " |