document.write( "Question 124607: I am working on solving linear and quadratic equations. I need help with this problem:\r
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\n" ); document.write( "\n" ); document.write( "I believe the CD:(y-2)(3y-2)(3y+2)\r
\n" ); document.write( "\n" ); document.write( "Please help solve. Thanks.
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Algebra.Com's Answer #91485 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume you mean:
\n" ); document.write( "\"%283y%2B1%29%2F%283y%5E2-4y-4%29\" + \"9%2F%289y%5E2-4%29\" = \"%282y-2%29%2F%283y%5E2-8y%2B4%29\"
\n" ); document.write( "Factor the denominators:
\n" ); document.write( "\"%283y%2B1%29%2F%28%283y%2B2%29%28y-2%29%29\" + \"9%2F%28%283y-2%29%283y%2B2%29%29\" = \"%282y-2%29%2F%28%283y-2%29%28y-2%29+%29\"
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\n" ); document.write( "You're right about the common denominator, multiply each term by that:
\n" ); document.write( "(y-2)(3y-2)(3y+2)*\"%283y%2B1%29%2F%28%283y%2B2%29%28y-2%29%29\" + (y-2)(3y-2)(3y+2)*\"9%2F%28%283y-2%29%283y%2B2%29%29\" = (y-2)(3y-2)(3y+2)*\"%282y-2%29%2F%28%283y-2%29%28y-2%29+%29\"
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\n" ); document.write( "Cancel out the denominators, leaving:
\n" ); document.write( "(3y-2)(3y+1) + 9(y-2) = (3y+2)(2y-2)
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\n" ); document.write( "FOIL
\n" ); document.write( "(9y^2 - 3y - 2) + (9y-18) = 6y^2 - 2y - 4
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\n" ); document.write( "Combine like terms on the left
\n" ); document.write( "9y^2 - 6y^2 - 3y + 9y + 2y - 2 - 18 + 4 = 0
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\n" ); document.write( "3y^2 + 8y - 16 = 0
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\n" ); document.write( "Factors to:
\n" ); document.write( "(3y - 4)(y + 4) = 0
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\n" ); document.write( "3y = +4
\n" ); document.write( "y = \"4%2F3\"
\n" ); document.write( "and
\n" ); document.write( "y = -4
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\n" ); document.write( "I checked the y=-4 solution in the original equation.
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\n" ); document.write( "Did this help you?
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