document.write( "Question 124548: I am so confused...I need to solve each system by the addition method, I am only understanding half of the process.\r
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Algebra.Com's Answer #91476 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Are you sure you have this problem written correctly? Could it be: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "GEt rid of the denominators by multiplying equation by 12 \n" ); document.write( "12* \n" ); document.write( ": \n" ); document.write( "Cancel the denominators and you have: \n" ); document.write( "3x + 4y = 60 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation (x-y=6), by 4 and add to the above equation \n" ); document.write( "3x + 4y = 60 \n" ); document.write( "4x - 4y = 24 \n" ); document.write( "---------------- adding eliminates y \n" ); document.write( "7x + 0y = 84 \n" ); document.write( "7x = 84 \n" ); document.write( "x = \n" ); document.write( "x = 12 \n" ); document.write( ": \n" ); document.write( "Find y using x - y = 6; substitute 12 for y \n" ); document.write( "12 - y = 6 \n" ); document.write( "-y = 6 - 12 \n" ); document.write( "-y = -6 \n" ); document.write( "y = +6; multiplied equation by -1 to get rid of the negatives \n" ); document.write( ": \n" ); document.write( "Now let's check our solutions in the original equations: \n" ); document.write( " \n" ); document.write( " 3 + 2 = 5; confirms our solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Did this unconfuse you? Any questions?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |