document.write( "Question 124548: I am so confused...I need to solve each system by the addition method, I am only understanding half of the process.\r
\n" ); document.write( "\n" ); document.write( "\"1%2F4X+%2B+1%2F3y+=+5\"
\n" ); document.write( "\"x+-+y+=+6\"
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Algebra.Com's Answer #91476 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"1%2F4X+%2B+1%2F3y+=+5\"
\n" ); document.write( "\"x+-+y+=+6\"
\n" ); document.write( ":
\n" ); document.write( "Are you sure you have this problem written correctly? Could it be:
\n" ); document.write( "\"1%2F4\"x + \"1%2F3\"y = 5
\n" ); document.write( ":
\n" ); document.write( "GEt rid of the denominators by multiplying equation by 12
\n" ); document.write( "12*\"1%2F4\"x + 12*\"1%2F3\"y = 12(5)
\n" ); document.write( ":
\n" ); document.write( "Cancel the denominators and you have:
\n" ); document.write( "3x + 4y = 60
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation (x-y=6), by 4 and add to the above equation
\n" ); document.write( "3x + 4y = 60
\n" ); document.write( "4x - 4y = 24
\n" ); document.write( "---------------- adding eliminates y
\n" ); document.write( "7x + 0y = 84
\n" ); document.write( "7x = 84
\n" ); document.write( "x = \"84%2F7\"; divided both sides by 7
\n" ); document.write( "x = 12
\n" ); document.write( ":
\n" ); document.write( "Find y using x - y = 6; substitute 12 for y
\n" ); document.write( "12 - y = 6
\n" ); document.write( "-y = 6 - 12
\n" ); document.write( "-y = -6
\n" ); document.write( "y = +6; multiplied equation by -1 to get rid of the negatives
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\n" ); document.write( "Now let's check our solutions in the original equations:
\n" ); document.write( "\"1%2F4\"*12 + \"1%2F3\"*6 = 5
\n" ); document.write( " 3 + 2 = 5; confirms our solution
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\n" ); document.write( "Did this unconfuse you? Any questions?\r
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