document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124530>Question 124530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perform the indicated operation.\r<BR>\n" );
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document.write( "1) cubed root of 9x squared  TIMES  cubed root of 3x\r<BR>\n" );
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document.write( "2) ( 2 squared root of 3 MINUS 3)(2 square root of 3 + 3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91475 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perform the indicated operation.<BR>\n" );
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document.write( "1) cubed root of 9x squared TIMES cubed root of 3x<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=CubeRt%289x%5E2%29 ALIGN=MIDDLE  ALT=\"CubeRt%289x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > * <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=CubeRt%283x%29 ALIGN=MIDDLE  ALT=\"CubeRt%283x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "can be combined, do the math, and note that 27x^3 is a perfect cube<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=CubeRt%289x%5E2%2A3x%29 ALIGN=MIDDLE  ALT=\"CubeRt%289x%5E2%2A3x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=CubeRt%2827x%5E3%29 ALIGN=MIDDLE  ALT=\"CubeRt%2827x%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 3x <BR>\n" );
document.write( ":\r<BR>\n" );
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document.write( "2) ( 2 squared root of 3 MINUS 3)(2 square root of 3 + 3)<BR>\n" );
document.write( "(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Asqrt%283%29+-+3 ALIGN=MIDDLE  ALT=\"2%2Asqrt%283%29+-+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >)(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2%2Asqrt%283%29+%2B+3 ALIGN=MIDDLE  ALT=\"+2%2Asqrt%283%29+%2B+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
document.write( "FOIL this<BR>\n" );
document.write( "4(3) + 6<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > - 6*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > - 9<BR>\n" );
document.write( "Note that the two radicals in the middle have opposite signs so they cancel, leaving:<BR>\n" );
document.write( "12 - 9 = 3<BR>\n" );
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document.write( "Did this make sense to you? Any questions? </SPAN>\n" );
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