document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124721>Question 124721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (5)  Two cars enter the Florida Turnpike at Commercial Boulevard at 8:00 am, each heading for Wildwood.  One car’s average speed is 10 miles per hour more than the other’s.  The faster car arrives at Wildwood at 11:00 am, ½ hour before the other car.  What was the average speed of each car?  How far did each travel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91434 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the faster car=3(r+10)<BR>\n" );
document.write( "the slower car=3.5*r<BR>\n" );
document.write( "seeing as the distances are the same we set these 2 equations equal to each other.<BR>\n" );
document.write( "3(r+10)=3.5r<BR>\n" );
document.write( "3r+30=3.5r<BR>\n" );
document.write( "3r-3.5r=-30<BR>\n" );
document.write( "-.5r=-30<BR>\n" );
document.write( "r=-30/-.5<BR>\n" );
document.write( "r= 60 mph is the speed of the slower car.<BR>\n" );
document.write( "60+10=70mph is the speed of the faster car.<BR>\n" );
document.write( "distance=3*70=210 miles.<BR>\n" );
document.write( "distabce=60*3.5=210 miles.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );