document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124695>Question 124695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I be able to find the surface area of a hockey rink that is 100 feet by 200 feet, with quarter cirlces in the corners that have a radius of  20 feet?\r<BR>\n" );
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document.write( "Thank you very, very much!!! :-)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91425 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The rink is 100*200=20,000ft^2<BR>\n" );
document.write( "The 4 quarter circles in the corners equals one circle with a radius=20.<BR>\n" );
document.write( "Thus we have to subtract one circle with radius=20 ft<BR>\n" );
document.write( "area=pi*r^2<BR>\n" );
document.write( "area=3.14*20^2<BR>\n" );
document.write( "area=3.14*400<BR>\n" );
document.write( "area=1,256<BR>\n" );
document.write( "20,000-1,256=18,744 ft^2 is the remaining area of the rink.   </SPAN>\n" );
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