document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124694>Question 124694</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stan invested $26,000, part at 11% and part at 8%.  If the total interest at the end of the year is $2,560, how much did he invest at 11%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91401 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Stan invested $26,000, part at 11% and part at 8%. If the total interest at the end of the year is $2,560, how much did he invest at 11%?<BR>\n" );
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document.write( "Let \"x\" be amt. at 11% ; interest = 0.11x dollars<BR>\n" );
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document.write( "Amt at 8% is \"26000-x\" ; interest is 0.08(26000-x)= 2080-0.08x dollars<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "interest + interet = 2560 dollars<BR>\n" );
document.write( "0.11x + 2080-0.08x = 2560<BR>\n" );
document.write( "0.03x = 480<BR>\n" );
document.write( "x = $16000 (amt. invested at 11%)<BR>\n" );
document.write( "26000-16000= $10,000 (amt invested at 8%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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