document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124673>Question 124673</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321369580/algebrahomeworkh>college algerbra in context</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> from the book. for the function y=xsquard, compute the average rate of change between x=0 and x=3 can you explain how to do this simply? because i can not undersatnd it from the book. thanks to anyone </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91389 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the average rate of change for a function between two given points, you compute the slope of the secant line, that is the line that passes through the two points.\r<BR>\n" );
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document.write( "For your function, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29=y=x%5E2 ALIGN=MIDDLE  ALT=\"f%28x%29=y=x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the value of the function at <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=0 ALIGN=MIDDLE  ALT=\"x=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%280%29=0%5E2=0 ALIGN=MIDDLE  ALT=\"f%280%29=0%5E2=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  So your first point is (0,0)\r<BR>\n" );
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document.write( "The value of the function at <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=3 ALIGN=MIDDLE  ALT=\"x=3\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%283%29=3%5E2=9 ALIGN=MIDDLE  ALT=\"f%283%29=3%5E2=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so your second point is (3,9)\r<BR>\n" );
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document.write( "The slope of the line is given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=DELTA%2Ay%2F%28DELTA%2Ax%29=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"DELTA%2Ay%2F%28DELTA%2Ax%29=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%289-0%29%2F%283-0%29=3 ALIGN=MIDDLE  ALT=\"%289-0%29%2F%283-0%29=3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Therefore your average rate of change is 3.\r<BR>\n" );
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document.write( "The green line is the secant line and the red curve is the original function.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28200%2C400%2C-2%2C5%2C-2%2C10%2Cx%5E2%2C3x%29 ALIGN=MIDDLE  ALT=\"graph%28200%2C400%2C-2%2C5%2C-2%2C10%2Cx%5E2%2C3x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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