document.write( "Question 124553: A dealer mixed some coffee worth $.80 per pound with coffee worth $.50 per pound to make a mixture to be sold for $.70 per pound. If the number of pounds of $.80 coffee was 10 more than the number of ponds of the $.50 coffee how many pounds of each kind did he use? \n" ); document.write( "
Algebra.Com's Answer #91374 by ankor@dixie-net.com(22740)\"\" \"About 
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A dealer mixed some coffee worth $.80 per pound with coffee worth $.50 per pound to make a mixture to be sold for $.70 per pound. If the number of pounds of $.80 coffee was 10 more than the number of ponds of the $.50 coffee how many pounds of each kind did he use?
\n" ); document.write( ":
\n" ); document.write( "Let x = no. of lbs of $.50 coffee
\n" ); document.write( "and
\n" ); document.write( "(x+10) = no. of lbs of $.80 coffee
\n" ); document.write( "Then
\n" ); document.write( "(2x+10) = total lbs of the final mixture
\n" ); document.write( ":
\n" ); document.write( ".50x + .80(x+10) = .70(2x+10)
\n" ); document.write( ":
\n" ); document.write( ".50x + .80x + 8 = 1.4x + 7
\n" ); document.write( ":
\n" ); document.write( "1.3x - 1.4x = 7 - 8
\n" ); document.write( ":
\n" ); document.write( "-.1x = -1
\n" ); document.write( "x = \"%28-1%29%2F%28-.1%29\"
\n" ); document.write( "x = +10 lbs of $.70 coffee
\n" ); document.write( "then
\n" ); document.write( "10 + 10 = 20 lbs of $.80 coffee
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution
\n" ); document.write( ".5(10) + .8(20) = .7(30)
\n" ); document.write( " 5 + 16 = 21\r
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