document.write( "Question 124652: Solve.\r
\n" ); document.write( "\n" ); document.write( "1) m squared - 6m = 16\r
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\n" ); document.write( "\n" ); document.write( "2) x squared + 5x = 3
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Algebra.Com's Answer #91373 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "\"m%5E2-6m=16\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"m%5E2-6m-16=0\" Subtract 16 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%28m-8%29%28m%2B2%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"m-8=0\" or \"m%2B2=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"m=8\" or \"m=-2\" Now solve for m in each case\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \r
\n" ); document.write( "\n" ); document.write( " \"m=8\" or \"m=-2\" \r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=x%5E2-6x-16\" (just replace m with x) we can see that the roots are \"x=8\" and \"x=-2\" . So this visually verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+x%5E2-6x-16%29+\"\r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B5x=3\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B5x-3=0\" Subtract 3 from both sides. \r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B5%2Ax-3=0\" ( notice \"a=1\", \"b=5\", and \"c=-3\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+%285%29%5E2-4%2A1%2A-3+%29%29%2F%282%2A1%29\" Plug in a=1, b=5, and c=-3\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25-4%2A1%2A-3+%29%29%2F%282%2A1%29\" Square 5 to get 25 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25%2B12+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-3%2A1\" to get \"12\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+37+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%2837%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%2837%29%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B+sqrt%2837%29%29%2F2\" or \"x+=+%28-5+-+sqrt%2837%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=-5%2F2%2Bsqrt%2837%29%2F2\" or \"x=-5%2F2-sqrt%2837%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=0.54138126514911\" or \"x=-5.54138126514911\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0.54138126514911\" or \"x=-5.54138126514911\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B5%2Ax-3\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=0.54138126514911\" and \"x=-5.54138126514911\".So this verifies our answer
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