document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18985>Question 18985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> four numbers have a total of 92.  The first number is twice the second number and the third number is 4 times more than the sum of the first two.  The fourth number is 3 less than the difference of the first two numbers.  What is the difference?  \r<BR>\n" );
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document.write( "I have access to the answer and after I have that I can do it...but I can not for the life of me figure how to get the fist number. I am doing a series of these problems and Im almost in tears...please help!  Thank you!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9135 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the Second number = X<BR>\n" );
document.write( "Now, the first number = 2X (since first number is twice the second number)<BR>\n" );
document.write( "The third number = (X+2X)+ 4 = 3X +4 (third number is 4 times more than the sum of the first two)<BR>\n" );
document.write( "The fourth number = 2X-X -3  = x-3(since it is 3 less than the difference of the first two numbers)\r<BR>\n" );
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document.write( "And finally we have the sum of all the numbers = 92\r<BR>\n" );
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document.write( "i.e. X+2X+3X +4 +X-3 =92<BR>\n" );
document.write( "7x = 92-1<BR>\n" );
document.write( "7x = 91\r<BR>\n" );
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document.write( "OR X = 13\r<BR>\n" );
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document.write( "Can you find out the rest of the numbers? Simply substitute 13 in the rest of the numbers to get their values. </SPAN>\n" );
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