document.write( "Question 124427: Can anyone help me solve this equation?
\n" ); document.write( "160x=3x + the sqaure root of 50x+9000\r
\n" ); document.write( "\n" ); document.write( "160x-3x=the square root of 50x + 9000 is all the farther I've gotten. I think I square both sides now to get rid of the square root symbol, but do I need to simplify it first and if so, how? \n" ); document.write( "
Algebra.Com's Answer #91322 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
160x=3x + the sqaure root of 50x+9000
\n" ); document.write( ":
\n" ); document.write( "160x-3x=the square root of 50x + 9000
\n" ); document.write( "which is:
\n" ); document.write( "157x = sqrt(50x+9000)
\n" ); document.write( ":
\n" ); document.write( "Square it:
\n" ); document.write( "24649x^2 = 50x + 9000
\n" ); document.write( ":
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "24649x^2 - 50x - 9000 = 0
\n" ); document.write( ":
\n" ); document.write( "you have to use the quadratic formula to solve it:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this equation a=24649; b=-50; c=-9000
\n" ); document.write( "\"x+=+%28-%28-50%29+%2B-+sqrt%28-50%5E2-+4+%2A+24649+%2A+-9000+%29%29%2F%282%2A24649%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%2850+%2B-+sqrt%282500+-+%28-887364000%29+%29%29%2F%2849298%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%2850+%2B-+sqrt%282500+%2B+887364000+%29%29%2F%2849298%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%2850+%2B-+sqrt%28887336500%29%29%2F%2849298%29+\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"x+=+%2850+%2B+29788.7%29%2F%2849298%29+\"
\n" ); document.write( "\"x+=+%2829838.7%29%2F%2849298%29+\"
\n" ); document.write( "x = +.605
\n" ); document.write( "and
\n" ); document.write( " \"x+=+%2850+-+29788.7%29%2F%2849298%29+\"
\n" ); document.write( "\"x+=+%28-29738.7%29%2F%2849298%29+\"
\n" ); document.write( "x = -.603
\n" ); document.write( ":
\n" ); document.write( "I checked these solutions on a Ti83 graphing calc. You can confirm it yourself
\n" ); document.write( "by substitution in the original equation\r
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