document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124587>Question 124587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for y:<BR>\n" );
document.write( "2x+y=3\r<BR>\n" );
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document.write( "also this one....\r<BR>\n" );
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document.write( "solve for h:<BR>\n" );
document.write( "s=5ph\r<BR>\n" );
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document.write( "I'm really confused since I can figure out what to do with the other variables that are not supposed to be solved. Maybe you could help me out and explain...<BR>\n" );
document.write( "thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91316 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+y=3 <BR>\n" );
document.write( "now subtract 2x from both sides<BR>\n" );
document.write( "2x-2x+y=-2x+3 now add the -2x & the +2x which =0.<BR>\n" );
document.write( "y=-2x+3 answer.<BR>\n" );
document.write( "s=5ph now divide both sides by 5p<BR>\n" );
document.write( "s/5p=5ph/5p now cancel out the 5p/5p on the right side of the equation.  <BR>\n" );
document.write( "s/5p=h answer. </SPAN>\n" );
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