document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124563>Question 124563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of candyworth $3.60 per pound must be added to 10 pounds of chocolate worth $2.40 per pound to form a mixture worth $3.30 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91306 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.6x+2.4*10=3.3(x+10)<BR>\n" );
document.write( "3.6x+24=3.3x+33<BR>\n" );
document.write( "3.6x-3.3x=33-24<BR>\n" );
document.write( ".3x=9<BR>\n" );
document.write( "x=9/.3<BR>\n" );
document.write( "x=30 pounds of $3.60 candy is needed.<BR>\n" );
document.write( "proof.<BR>\n" );
document.write( "3.6*30+2.4*10=3.3*40<BR>\n" );
document.write( "108+24=132<BR>\n" );
document.write( "132=132\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );