document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124567>Question 124567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A dealer mixed some coffee worth $.80 per pound with coffee worth $.50 per pound to make a mixture to be sold for $.70 per pound. If the number of pounds of $.80 coffee was 10 more than the number of pounds of the $.50 coffee, how many pounds of each kind did he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91299 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .8(x+10)+.5x=.7(2x+10)<BR>\n" );
document.write( ".8x+8+.5x=1.4x+7<BR>\n" );
document.write( ".8x+.5x-1.4x=7-8<BR>\n" );
document.write( "-.1x=-1<BR>\n" );
document.write( "x=-1/-.1<BR>\n" );
document.write( "x=10 pounds of $.50 coffee is used.<BR>\n" );
document.write( "10+10=20 pounds of $.80 coffee is used.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( ".8*20+.5*10=.7*30<BR>\n" );
document.write( "16+5=21<BR>\n" );
document.write( "21=21<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );