document.write( "Question 124567: A dealer mixed some coffee worth $.80 per pound with coffee worth $.50 per pound to make a mixture to be sold for $.70 per pound. If the number of pounds of $.80 coffee was 10 more than the number of pounds of the $.50 coffee, how many pounds of each kind did he use? \n" ); document.write( "

Algebra.Com's Answer #91298 by Earlsdon(6294) $\"\"$ $\"About$

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Start by letting x = the number of pounds of the $0.50 per pound coffee.
\n" ); document.write( "The the number of pounds of the $0.08 per pound coffee can be expressed by (x+10)
\n" ); document.write( "The sum of these two quantities (x+x+10)is to equal the number of pounds of coffee at $0.70 per pound.
\n" ); document.write( "We can write the following equation:
\n" ); document.write( " $\"%280.50%29x+%2B+%280.80%29%28x%2B10%29+=+%28x%2Bx%2B10%29%280.70%29\"$ Simplify this and solve for x.
\n" ); document.write( " $\"0.5x%2B0.8x%2B8+=+0.7%282x%2B10%29\"$
\n" ); document.write( " $\"1.3x%2B8+=+1.4x%2B7\"$ subtract 1.3x from both sides.
\n" ); document.write( " $\"8+=+0.1x%2B7\"$ Subtract 7 from both sides.
\n" ); document.write( " $\"1+=+0.1x\"$ Divide both sides by 0.1
\n" ); document.write( " $\"10+=+x\"$
\n" ); document.write( "The dealer will need to mix 10 pounds of the $0.50 per pound coffee (x+10) 20 pounds of the $0.80 per pound coffee to obtain 30 pounds of $0.70 per pound coffee. \n" ); document.write( "

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