document.write( "Question 124525: The area of a rectangle is 40.if the length is 6 more than the width, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #91287 by iluvbuilding429(41)![]() ![]() ![]() You can put this solution on YOUR website! The area of a rectangle is 40.if the length is 6 more than the width, find the dimensions of the rectangle. \r \n" ); document.write( "\n" ); document.write( "Ok, so you know that \r \n" ); document.write( "\n" ); document.write( "Plug this and your known area into the formula for area of a rectangle which is: \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Here it is with the values plugged in: \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Multiply: \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Add: \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Divide both sides by 7: \n" ); document.write( "5 5/7=w \r \n" ); document.write( "\n" ); document.write( "Just add 6 to that to find your length, which is 11 5/7.\r \n" ); document.write( "\n" ); document.write( "And there's your answer. \r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "40=5 5/7+6*5 5/7 \r \n" ); document.write( "\n" ); document.write( "Multiply: \n" ); document.write( "40=5 5/7+34 2/7 \r \n" ); document.write( "\n" ); document.write( "Add: \n" ); document.write( " |