document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124543>Question 124543</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321356896/algebrahomeworkh>A Graphical Approach to College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wishes to strengthen a mixture from 10% alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of the 10% mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91277 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the required number of liters of pure alcohol to be added to the 7 liters of 10% alcohol solution to get (7+x) liters of 30% alcohol solution.<BR>\n" );
document.write( "The 7 liters of 10% alcohol solution can be expressed as:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%280.1%29 ALIGN=MIDDLE  ALT=\"7%280.1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and we'll add x liters of 100% alcohol to this to get the (7+x)(0.3) liters.<BR>\n" );
document.write( "So, here's the equation:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%280.1%29%2Bx+=+%287%2Bx%29%280.3%29 ALIGN=MIDDLE  ALT=\"7%280.1%29%2Bx+=+%287%2Bx%29%280.3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify and solve for x.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.7%2Bx+=+2.1%2B0.3x ALIGN=MIDDLE  ALT=\"0.7%2Bx+=+2.1%2B0.3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 0.3x from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.7%2B0.7x+=+2.1 ALIGN=MIDDLE  ALT=\"0.7%2B0.7x+=+2.1\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now subtract 0.7 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.7x+=+1.4 ALIGN=MIDDLE  ALT=\"0.7x+=+1.4\"   DISABLED_style= \"max-width:90%; height:auto;\" > Finally, divide both sides by 0.7<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2 ALIGN=MIDDLE  ALT=\"x+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The chemist will need to add 2 liters of pure alcohol to the 7 liters of the 10% alcohol solution to obtain 9 liters of 30% alcohol solution.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%280.1%29%2B2+=+%287%2B2%29%280.3%29 ALIGN=MIDDLE  ALT=\"7%280.1%29%2B2+=+%287%2B2%29%280.3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.7%2B2+=+9%280.3%29 ALIGN=MIDDLE  ALT=\"0.7%2B2+=+9%280.3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.7+=+2.7 ALIGN=MIDDLE  ALT=\"2.7+=+2.7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );