document.write( "Question 124538This question is from textbook
\n" ); document.write( ": A person can drive from town A to town B at a certain rate of speed in 6 hours. If he increases his speed by 20kph he can make the trip in four hours. How far is it from town A to B. \n" ); document.write( "
Algebra.Com's Answer #91275 by Earlsdon(6294)\"\" \"About 
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Use the distance formula on this problem:
\n" ); document.write( "\"d+=+rt\" where:d = distance, r = rate(speed) and t = time of travel.
\n" ); document.write( "For the first trip:
\n" ); document.write( "\"t%5B1%5D+=+6\" and we don't know \"r%5B1%5D\"
\n" ); document.write( "For the second trip:
\n" ); document.write( "\"t%5B2%5D+=+4\" and \"r%5B2%5D+=+r%5B1%5D%2B20\"
\n" ); document.write( "and, of course, d is the same in both cases.
\n" ); document.write( "So, we can write:
\n" ); document.write( "1) \"d+=+6r%5B1%5D\" and...
\n" ); document.write( "2) \"d+=+4%28r%5B1%5D%2B20%29\" setting these two equal to each other and simplifying...
\n" ); document.write( "\"6r%5B1%5D+=+4r%5B1%5D%2B80\" Subtract \"4r%5B1%5D\" from both sides.
\n" ); document.write( "\"2r%5B1%5D+=+80\" Divide both sides by 2.
\n" ); document.write( "\"r%5B1%5D+=+40\" Now we can find the distance, d.
\n" ); document.write( "\"d+=+r%5B1%5Dt%5B1%5D\" Substitute \"r%5B1%5D+=+40\"and\"t%5B1%5D+=+6\"
\n" ); document.write( "\"d+=+40%2A6\"
\n" ); document.write( "\"d+=+240\"km.
\n" ); document.write( "Check: Substitute \"r%5B2%5D+=+r%5B1%5D%2B20\" and \"t%5B2%5D+=+4\"
\n" ); document.write( "\"d+=+r%5B2%5Dt%5B2%5D\"
\n" ); document.write( "\"d+=+%2840%2B20%29%2A4\"
\n" ); document.write( "\"d+=+60%2A4\"
\n" ); document.write( "\"d+=+240\"km.
\n" ); document.write( "The distance from town A to town B is 240 km.\r
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