document.write( "Question 124539: The number N, in millions, of hearing impaired individuals of age x can be approximated by:\r
\n" ); document.write( "\n" ); document.write( "N = -0.00006x^3 + 0.006x^2 - 0.1x + 1.3\r
\n" ); document.write( "\n" ); document.write( "Approximate to the nearest million the number of hearing impaired individuals of ages 50 - 60.\r
\n" ); document.write( "\n" ); document.write( "N = (squiggly lines) ___________ million individuals of age 50.\r
\n" ); document.write( "\n" ); document.write( "N = (squiggly lines) ___________ million individuals of age 60.\r
\n" ); document.write( "\n" ); document.write( "Please help, I submitted this yesterday and noone seemed to have answered. I tried calculating and kept coming up with 0 and that can't be the answer.\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #91273 by Earlsdon(6294)\"\" \"About 
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\"N+=+-0.00006x%5E3%2B0.006x%5E2-0.1x%2B1.3\" Substitute x = 50
\n" ); document.write( "\"N+=+-0.00006%2850%29%5E3%2B0.006%2850%29%5E2-0.1%2850%29%2B1.3\"
\n" ); document.write( "\"N+=+-7.5%2B15-5%2B1.3\"
\n" ); document.write( "\"N+=+3.8\" round to the nearest million...
\n" ); document.write( "\"N+=+4\"Million, approximately.
\n" ); document.write( "\"N+=+-0.00006x%5E3%2B0.006x%5E2-0.1x%2B1.3\" Substitute x = 60
\n" ); document.write( "\"N+=+-0.00006%2860%29%5E3%2B0.006%2860%29%5E2-0.1%2860%29%2B1.3\"
\n" ); document.write( "\"N+=+-12.96%2B21.6-6%2B1.3\"
\n" ); document.write( "\"N+=+3.94\" Round to the nearest million...
\n" ); document.write( "\"N+=+4\"Million, approximately.
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