document.write( "Question 124504: 11 years ago, Hye was four times as old as her brother. In 1 year she will be twice as old as he is now. What are their ages now? \n" ); document.write( "
Algebra.Com's Answer #91258 by checkley71(8403)\"\" \"About 
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11 YEARS AGE HYE=4X & HER BROTHER=X.
\n" ); document.write( "12 YEARS LATER HYE=(4X+12) & HER BROTHER=(X+12).
\n" ); document.write( "SO (4X+12)=2(X+12)
\n" ); document.write( "4X+12=2X+24
\n" ); document.write( "4X-2X=24-12
\n" ); document.write( "2X=12
\n" ); document.write( "X=6 WHICH IS HER BROTHERS AGE 11 YEARS AGO.
\n" ); document.write( "HYE'S AGE 11 YEARS AGO=4*6=24.
\n" ); document.write( "PROOF:
\n" ); document.write( "24+12=2(6+12)
\n" ); document.write( "36=2*18
\n" ); document.write( "36=36\r
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