document.write( "Question 124504: 11 years ago, Hye was four times as old as her brother. In 1 year she will be twice as old as he is now. What are their ages now? \n" ); document.write( "
Algebra.Com's Answer #91258 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 11 YEARS AGE HYE=4X & HER BROTHER=X. \n" ); document.write( "12 YEARS LATER HYE=(4X+12) & HER BROTHER=(X+12). \n" ); document.write( "SO (4X+12)=2(X+12) \n" ); document.write( "4X+12=2X+24 \n" ); document.write( "4X-2X=24-12 \n" ); document.write( "2X=12 \n" ); document.write( "X=6 WHICH IS HER BROTHERS AGE 11 YEARS AGO. \n" ); document.write( "HYE'S AGE 11 YEARS AGO=4*6=24. \n" ); document.write( "PROOF: \n" ); document.write( "24+12=2(6+12) \n" ); document.write( "36=2*18 \n" ); document.write( "36=36\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |