document.write( "Question 124386: Cost of car depends on km driven. Write lineqr equation expressing dollars per month as function of km per month if given $158 month if drive 300 km and $230 a month if drive 1500 km. Predict cost for 1000 ad 2000 km driven a month. \n" ); document.write( "
Algebra.Com's Answer #91257 by checkley71(8403) ![]() You can put this solution on YOUR website! SERTING UP X & Y VALUES FOR EACH SITUATION WE HAVE: \n" ); document.write( "(158,300) & (230,1500) \n" ); document.write( "NOW WE FIND THE SLOPE: \n" ); document.write( "(1500-300)/(230-158)=1200/72=16.67 \n" ); document.write( "(1000-300)/(X-158)=16.67 \n" ); document.write( "16.67(X-158)=700 \n" ); document.write( "16.67X-2633.86=700 \n" ); document.write( "16.67X=700+2633.86 \n" ); document.write( "16.67X=3333.86 \n" ); document.write( "X=3333.86/16.67 \n" ); document.write( "X=$200 COST FOR DRIVING 1000KMs. \n" ); document.write( "---------------------------------- \n" ); document.write( "(2000-300)/(X-158)=16.67 \n" ); document.write( "16.67(X-158)=1700 \n" ); document.write( "16.67X-2633.86=1700 \n" ); document.write( "16.67X=1700+2633.86 \n" ); document.write( "16.67X=4333.86 \n" ); document.write( "X=4333.86/16.67 \n" ); document.write( "X=$260 COST FOR DRIVING 2000KMs. \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |