document.write( "Question 124497: Mr. Lee is 27 years older than his son. In ten years,he will be twice as old as his son how old each? \n" ); document.write( "
Algebra.Com's Answer #91245 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=son's present age; x+10=son's age in 10 years
\n" ); document.write( "Then x+27=Mr. Lee's present age; x+37=Mr. Lee's age in 10 years\r
\n" ); document.write( "\n" ); document.write( "Now we are told the following:\r
\n" ); document.write( "\n" ); document.write( "x+37=2(x+10) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "x+37=2x+20 subtract 20 and also x from each side
\n" ); document.write( "x-x+37-20=2x-x+20-20 collect like terms\r
\n" ); document.write( "\n" ); document.write( "17=x or
\n" ); document.write( "x=17---------------------son's present age
\n" ); document.write( "x+27=17+27=44----------------Mr. Lee's present age\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "44-17=27
\n" ); document.write( "27=27
\n" ); document.write( "also
\n" ); document.write( "44+10=2*27
\n" ); document.write( "54=54\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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