document.write( "Question 124469This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": Suppose Charle O'Brian hits a baseball straight upward at 150 ft/sec from a height of 5 ft.
\n" ); document.write( "Use the formula to determine how long it takes the ball to return to the earth.\r
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Algebra.Com's Answer #91231 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
The equation you are looking for is:
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\n" ); document.write( "\"h%28t%29+=+-16t%5E2+%2B+V%5Bo%5Dt+%2B+h%5Bo%5D\"
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\n" ); document.write( "\"V%5Bo%5D\" is the initial velocity of + 150 ft/s and \"h%5Bo%5D\" is the initial height of 5 ft.
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\n" ); document.write( "Substituting these values into the equation results in:
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\n" ); document.write( "\"h%28t%29+=+-16t%5E2+%2B+150t+%2B+5\"
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\n" ); document.write( "in which \"h%28t%29\" represents the height of the ball above the ground at time t.
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\n" ); document.write( "You are interested in finding the time it takes for the ball to rise up as high as it will go, and
\n" ); document.write( "then finally fall back to the ground where its height will be zero feet. So substitute
\n" ); document.write( "zero for \"h%28t%29\" and the equation becomes:
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\n" ); document.write( "\"0+=+-16t%5E2+%2B+150t+%2B+5\"
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\n" ); document.write( "which (by switching sides) in the more standard form of a quadratic equation is:
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\n" ); document.write( "\"-16t%5E2+%2B+150t+%2B+5+=+0\"
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\n" ); document.write( "This in standard form of \"at%5E2+%2B+bt+%2B+c\" in which a = -16, b = +150, and c = 5. The quadratic
\n" ); document.write( "formula tells you that for such standard form quadratic equations the answers for t will be
\n" ); document.write( "in the form:
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\n" ); document.write( "\"t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "Substitute the above values for a, b, and c and the equation becomes:
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\n" ); document.write( "\"t+=+%28-150+%2B-+sqrt%28+150%5E2-4%2A%28-16%29%2A5+%29%29%2F%282%2A%28-16%29%29+\"
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\n" ); document.write( "Determine the term under the radical. \"150%5E2+=+22500\" and \"%28-4%29%2A%28-16%29%285%29=320\".
\n" ); document.write( "So the term under the radical becomes \"22500+%2B+320+=+22820\". Substitute this and the equation is:
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\n" ); document.write( "\"t+=+%28-150+%2B-+sqrt%28+22820%29%29%2F%282%2A%28-16%29%29+\"
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\n" ); document.write( "And \"sqrt%2822820%29+=+151.0629008\"
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\n" ); document.write( "Substitute this square root into the equation and you get:
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\n" ); document.write( "\"t+=+%28-150+%2B-+151.0629008%29%2F%282%2A%28-16%29%29\"
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\n" ); document.write( "The denominator multiplies out to -32 which makes the equation for t become:
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\n" ); document.write( "\"t+=+%28-150+%2B-+151.0629008%29%2F%28-32%29%29\"
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\n" ); document.write( "t must be a positive value (negative t doesn't make sense). Since the denominator is
\n" ); document.write( "negative, the numerator must also be negative to give a positive answer for t. The only way
\n" ); document.write( "to make the numerator negative is if both terms in the numerator are negative. Therefore, you
\n" ); document.write( "can forget about the + sign in the numerator and you only need to solve the equation:
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\n" ); document.write( "\"t+=+%28-150+-+151.0629008%29%2F%28-32%29%29\"
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\n" ); document.write( "Combining the two terms in the numerator results in:
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\n" ); document.write( "\"t+=+%28-301.0629008%29%2F%28-32%29\"
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\n" ); document.write( "and dividing the numerator by the denominator results in an answer of:
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\n" ); document.write( "\"t+=+9.40821565\"
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\n" ); document.write( "This rounds of to an answer of \"t+=+9.41\" seconds.
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\n" ); document.write( "Hope this helps you to understand the problem.
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