document.write( "Question 124470This question is from textbook Elementary and Intermediate Algebra
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document.write( ": The members of a flying club plan to share equally the cost of $200000 airplane. The members want to find five more people to join the club so that the cost per person will decrease by $2000. How many members are curently in the club? \n" );
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Algebra.Com's Answer #91219 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! (200,000/x)=200,000/(x+5)+2,000 \n" ); document.write( "(200,000/x)=(200,000+2,000[x+5])/(x+5) \n" ); document.write( "(200,000/x)=(200,000+2,000x+10,000)/(x+5) \n" ); document.write( "(200,000/x)=(210,000+2,000x)/(x+5) \n" ); document.write( "now cross multiply \n" ); document.write( "200,000(x+5)=(210,000+2,000x)x \n" ); document.write( "200,000x+1,000,000=210,000x+2,000x^2 \n" ); document.write( "2,000x^2+210,000x-200,000x-1,000,000=0 \n" ); document.write( "2,000x62+10,000x-1,000,000=0 \n" ); document.write( "2,000(x^2+5x-500)=0 \n" ); document.write( "2,000(x+25)(x-20)=0 \n" ); document.write( "x-20=0 \n" ); document.write( "x=20 the number of original club members. \n" ); document.write( "proof \n" ); document.write( "200,000/20=(200,000/25)+2000 \n" ); document.write( "10,000=8,000+2,000 \n" ); document.write( "10,000=10,000 \n" ); document.write( " \n" ); document.write( " |