document.write( "Question 124439: The equation h=-16t^2-32t+320
\n" ); document.write( "Give the height of a ball, thrown donward from top of a 320ft. Building with an initial velocity of 32ft/s. Find the time it takes for the ball to reach a height of 64ft.
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Algebra.Com's Answer #91189 by checkley71(8403)\"\" \"About 
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H=-16T^2-32T+320
\n" ); document.write( "64=-16T^2-32T+320
\n" ); document.write( "-16T^2-32T+320-64=0
\n" ); document.write( "-16T^2-32T+256=0
\n" ); document.write( "-16(T^2+2T-16)=0
\n" ); document.write( "USING THE QUADRATIC EQUATION:\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=(-2+-SQRT[2^2-4*1*-16])/2*1
\n" ); document.write( "X=(-2+-SQRT[4+64])/2
\n" ); document.write( "X=(-2+-SQRT68)/2
\n" ); document.write( "X=(-2+-8.246)/2
\n" ); document.write( "X=(-2+8.246)/2
\n" ); document.write( "X=6.246/2
\n" ); document.write( "X=3.123 SECONDS. ANSWER FOR THE TIME FOR THE BALL TO BE @ 64 FT FROM THE GROUND.\r
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