document.write( "Question 124433This question is from textbook Introductory Algebra
\n" ); document.write( ": Find an equation of the line that has the same y-intercept as the line x - 3y = 6 and contains the point (5,-1). \n" ); document.write( "

Algebra.Com's Answer #91187 by ilana(307) $\"\"$ $\"About$

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I am guessing you have learned the point-slope form of a linear equation, y-y1=m(x-x1), where m is the slope and (x1,x2) is the point. So, for your line, x1=5 and y1=-1. That means we just need m. We have the equation x-3y=6, but that does not immediately tell us the slope. But do you remember the first form of a linear equation you learned? It was probably y=mx+b, where m is the slope. This equation is very close to that, so let's just play with it until it looks exact, and then we'll see m, the slope.
\n" ); document.write( "First get the y term alone: -3y=6-x
\n" ); document.write( "Now divide by -3: y=-2+(1/3)x
\n" ); document.write( "Switch the terms so the x term is before the constant: y=(1/3)x-2
\n" ); document.write( "m=1/3
\n" ); document.write( "So we have a point and a slope- put it into the form at the beginning.
\n" ); document.write( "y+1=(1/3)(x-5)
\n" ); document.write( "This can also be written y+1=(x-5)/3 \n" ); document.write( "

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