document.write( "Question 124247This question is from textbook college algebra
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document.write( ": A total of $7500 is deposited into two simple interest accounts. On one account the annual simple interest rate of 5.5% and on the second account the annual simple interest rate is 7%. The amount of interest earned for 1 year was $405. How much was invested in each account. \n" );
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Algebra.Com's Answer #91136 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! SOMETHING IS WRONG WITH THIS PROBLEM!!!! IF YOU INVESTED THE $7500 ALL AT 5.5%, THE INTEREST ACCRUED WOULD BE: 7500*0.55*1 0R $412.50. WHEN YOU GET IT RIGHT, THE FOLLOWING WOULD BE THE APPROACH FOR SOLVING IT:\r \n" ); document.write( "\n" ); document.write( "Interest(I) equals Principal(P) times Rate(R) times Time(T) or I=PRT\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let P=amount deposited in the 5.5% account; Interest accrued on this account would be P*0.055*1 or 0.0.055P \n" ); document.write( "Then 7500-P=amount deposited in the 7% account; Interest accrued on this account would be (7500-P)*0.07*1 or 525-0.07P\r \n" ); document.write( "\n" ); document.write( "Now we are told that the total interest accrued on both accounts =$405. So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "0.055P+525-0.07P=405 subtract 525 from both sides \n" ); document.write( "0.055P-0.07P+525-525=405-525 collect like terms\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-0.015P=-120 divide both sides by -0.015\r \n" ); document.write( "\n" ); document.write( "P=$8000-----------------amount invested at 5.5% HELLO??????????????\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |