document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=124357>Question 124357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Long distance runner started a course running an average speed of 2mph. 1.33 hrs later, a cyclist traveled the same course at an average speed of 4mph. how many hrs after the runner started did the cyclist overtake the runner?<BR>\n" );
document.write( "round answer to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #91133 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=91133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r<BR>\n" );
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document.write( "Let t=time it takes cyclist to overtake runner AFTER the cyclist starts.<BR>\n" );
document.write( "And t+1.33 hr=time that we are looking for<BR>\n" );
document.write( "Distance runner runs before cyclist starts=2*1.33=2.66 mi\r<BR>\n" );
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document.write( "Total distance runner runs=2t+2.66<BR>\n" );
document.write( "Total distance cyclist travels=4t\r<BR>\n" );
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document.write( "We know that the cyclist will have overtaken the runner whe they have both travelled the same distance.  So our equation to solve is:\r<BR>\n" );
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document.write( "2t+2.66=4t  subtract 2t froom both sides\r<BR>\n" );
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document.write( "2t-2t+2.66=4t-2t  collect like terms\r<BR>\n" );
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document.write( "2t=2.66  divide both sides by 2\r<BR>\n" );
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document.write( "t=1.33 hr <BR>\n" );
document.write( "t+1.33hr=1.33hr+1.33hr=2.66hr=2.7hr-------------------ans\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "In 2.7 hr, runner runs2*2.66=5.32 mi<BR>\n" );
document.write( "In 1.33hr cyclist travels 4*1.33=5.32mi\r<BR>\n" );
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document.write( "Hope this helps--ptaylor </SPAN>\n" );
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