document.write( "Question 124254This question is from textbook Structure and Method Book 1
\n" ); document.write( ": For the function f(x)=x^2-2x+1
\n" ); document.write( "(a)find f(0)\r
\n" ); document.write( "\n" ); document.write( "(b)solve f(x)=0
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Algebra.Com's Answer #91129 by BrittanyM(80)\"\" \"About 
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For a, all we have to do is plug in zero for all values of x.\r
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\n" ); document.write( "\n" ); document.write( "\"0%5E2\" - 2(0) +1\r
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\n" ); document.write( "\n" ); document.write( "So a is 1.\r
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\n" ); document.write( "\n" ); document.write( "For b, we just have to set the equatin equal to zero and solve.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2\" - 2x + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "In order to solve for the values of x, we must factor.\r
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\n" ); document.write( "\n" ); document.write( "{x - 1)(x - 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "So for b, x = 1
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