document.write( "Question 124186: A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y \n" ); document.write( "
Algebra.Com's Answer #91100 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y \n" ); document.write( ": \n" ); document.write( "Let d = distance from x to y \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = \n" ); document.write( "Different speed roundtrip time = 1 speed roundtrip time + half/hour \n" ); document.write( " \n" ); document.write( "Multiply equation by 1800 to get rid of the denominators: \n" ); document.write( "1800* \n" ); document.write( "Cancel the denominators and you have: \n" ); document.write( ": \n" ); document.write( "36d + 45d = 40(2d) + 900 \n" ); document.write( ": \n" ); document.write( "81d = 80d + 900 \n" ); document.write( ": \n" ); document.write( "81d - 80d = 900 \n" ); document.write( ": \n" ); document.write( "d = 900 miles from x to y \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in: \n" ); document.write( " \n" ); document.write( " 18 + 22.5 = 40 + .5; confirms out solution \n" ); document.write( " \n" ); document.write( " |