document.write( "Question 124186: A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y \n" ); document.write( "
Algebra.Com's Answer #91100 by ankor@dixie-net.com(22740)\"\" \"About 
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A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y
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\n" ); document.write( "Let d = distance from x to y
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\n" ); document.write( "Write a time equation; time = \"distance%2Fspeed\"
\n" ); document.write( "Different speed roundtrip time = 1 speed roundtrip time + half/hour
\n" ); document.write( "\"d%2F50\" + \"d%2F40\" = \"2d%2F45\" + \"1%2F2\"
\n" ); document.write( "Multiply equation by 1800 to get rid of the denominators:
\n" ); document.write( "1800*\"d%2F50\" + 1800*\"d%2F40\" = 1800*\"2d%2F45\" + 1800*\"1%2F2\"
\n" ); document.write( "Cancel the denominators and you have:
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\n" ); document.write( "36d + 45d = 40(2d) + 900
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\n" ); document.write( "81d = 80d + 900
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\n" ); document.write( "81d - 80d = 900
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\n" ); document.write( "d = 900 miles from x to y
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\n" ); document.write( "Check solution in: \"d%2F50\" + \"d%2F40\" = \"2d%2F45\" + \"1%2F2\"
\n" ); document.write( "\"900%2F50\" + \"900%2F40\" = \"1800%2F45\" + \"1%2F2\"
\n" ); document.write( " 18 + 22.5 = 40 + .5; confirms out solution
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