document.write( "Question 124074: Artic Anitfreeze is 18% alcohol and Frost No More is 10% alcohol. How many liters of each should be mixed to get 20L of a mixture that is 15% alcohol? \n" ); document.write( "

Algebra.Com's Answer #91071 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Artic Anitfreeze is 18% alcohol and Frost No More is 10% alcohol. How many liters of each should be mixed to get 20L of a mixture that is 15% alcohol?
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\n" ); document.write( "Let x = amt of arctic
\n" ); document.write( "then
\n" ); document.write( "(20-x) = amt of frost
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\n" ); document.write( ".18x + .10(20-x) = .15(20)
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\n" ); document.write( ".18x + 2 - .10x = 3
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\n" ); document.write( ".18x - .10x = 3 - 2
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\n" ); document.write( ".08x = 1
\n" ); document.write( "x = $\"1%2F.08\"$
\n" ); document.write( "x = 12.5 liters of arctic r
\n" ); document.write( "and
\n" ); document.write( "20 - 12.5 = 7.5 liters of frost
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\n" ); document.write( "Check solution
\n" ); document.write( ".18(12.5) + .10(7.5) = .15(20)
\n" ); document.write( " 2.25 + .75 = 3; confirms our solution
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