document.write( "Question 124084: The rectangular ground floor of the John Hancock building has a perimeter of 860 ft. The length is 100ft more than the width. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #91067 by ankor@dixie-net.com(22740)\"\" \"About 
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The rectangular ground floor of the John Hancock building has a perimeter of 860 ft. The length is 100ft more than the width. Find the length and width.
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\n" ); document.write( "Let x = width
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\n" ); document.write( "It said,\"length is 100ft more than the width.\" therefore we can say
\n" ); document.write( "(x+100) = length
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\n" ); document.write( "Also,\"building has a perimeter of 860 ft.\"
\n" ); document.write( "2(x+100) + 2x = 860
\n" ); document.write( "2x + 200 + 2x = 860
\n" ); document.write( "4x = 860 - 200
\n" ); document.write( "4x = 660
\n" ); document.write( "x = \"660%2F4\"
\n" ); document.write( "x = 165 ft is the width
\n" ); document.write( "and
\n" ); document.write( "165 + 100 = 265 is the length
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\n" ); document.write( "Check solution in perimeter equation:
\n" ); document.write( "2(265) + 2(165) =
\n" ); document.write( "530 + 330 = 860
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