document.write( "Question 124264: What quantity x of a 75% acid solution must be mixed with a 25% solution to produce 500 ml of a 55% solution?\r
\n" ); document.write( "\n" ); document.write( "I have tried these equations
\n" ); document.write( ".75x+.25(.55*500)=500(.55)
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Algebra.Com's Answer #91052 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You are close, but since the final solution is 500 ml and the first quantity is x ml, then the second quantity is \"500-x\" ml\r
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\n" ); document.write( "\n" ); document.write( "So the equation should be\r
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\n" ); document.write( "\n" ); document.write( "\"0.75x%2B.25%28500-x%29=500%28.55%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.75x%2B.25%28500-x%29=275\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"0.75x%2B125-0.25x=275\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"0.50x%2B125=275\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"0.50x=150\" Subtract 125 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=300\" Divide both sides by 0.50 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "So you need 300 ml of the 75% solution
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