document.write( "Question 124081: A train leaves Danville Junction and travels north at a speed of 75km/hr. Two hours later, an express train leaves on a parallel track and travels north at 125km/hr. How far from the station will they meet? \n" ); document.write( "
Algebra.Com's Answer #91039 by ankor@dixie-net.com(22740)\"\" \"About 
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A train leaves Danville Junction and travels north at a speed of 75km/hr. Two hours later, an express train leaves on a parallel track and travels north at 125km/hr. How far from the station will they meet?
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\n" ); document.write( "Find out how many hrs until the one train overtakes the other
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\n" ); document.write( "t = travel time of the 1st train
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\n" ); document.write( "(t-2) = travel time of the 2nd train:
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\n" ); document.write( "When this happens they will have traveled the same distance;
\n" ); document.write( "write a distance equation: (Distance = speed * time)
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\n" ); document.write( "2nd train dist = 1st train dist
\n" ); document.write( "125(t-2) = 75t
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\n" ); document.write( "125t - 250 = 75t
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\n" ); document.write( "125t - 75t = + 250
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\n" ); document.write( "50t = 250
\n" ); document.write( "t = \"250%2F50\"
\n" ); document.write( "t = 5 hrs
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\n" ); document.write( "Use this, to find the distances:
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\n" ); document.write( "1st train: 5 * 75 = 375 mi
\n" ); document.write( "and
\n" ); document.write( "2nd train: 3 * 125 = 375 mi also; (confirms our solution)\r
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