document.write( "Question 124242: Solve by substitution or elimination:
\n" ); document.write( "x=3y+11
\n" ); document.write( "2x+5y=0
\n" ); document.write( "I dont understand could I please have help for this question?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #91034 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"x=3y%2B11\"
\n" ); document.write( "\"2x%2B5y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Substitution:
\n" ); document.write( "The first equation is already solved for x, so you can take the right-hand expression and substitute it for x into the second equation:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%2B5y=0\"
\n" ); document.write( "\"2%283y%2B11%29%2B5y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Simplify and solve:
\n" ); document.write( "\"6y%2B22%2B5y=0\"
\n" ); document.write( "\"11y%2B22=0\"
\n" ); document.write( "\"11y=-22\"
\n" ); document.write( "\"y=-2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now that you have a value for y, you can substitute that back into either equation to solve for x:
\n" ); document.write( "\"x=3%28-2%29%2B11\"
\n" ); document.write( "\"x=-6%2B11\"
\n" ); document.write( "\"x=5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solution set for this system is the ordered pair (5,-2)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Elimination:
\n" ); document.write( "Your second equation is in standard form (\"ax%2Bby=c\"), so put the first equation into standard form as well.\r
\n" ); document.write( "\n" ); document.write( "\"x=3y%2B11\"
\n" ); document.write( "\"x-3y=11\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. \"x-3y=11\"
\n" ); document.write( "2. \"2x%2B5y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The idea is to multiply one or both of the equations by a constant or constants so that the coefficients on one of the variables will become additive inverses. In this case, multiplying the first equation by -2 will give you a -2x in the first equation and 2x in the second equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3. \"-2x%2B6y=-22\"
\n" ); document.write( "2. \"2x%2B5y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now add the two equations, term by term:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "4. \"0x%2B11y=-22\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And solve:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"11y=-22\"
\n" ); document.write( "\"y=-2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now you can do either of two things. One, you can substitute this value for y back into either of the original equations and solve for x. Or two, you can go back to the original equations, find a different multiplier or multipliers that will allow you to eliminate the y variable and solve for x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We've already done the first way as the second step of the substitution method, so let's try the second way:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. \"x-3y=11\"
\n" ); document.write( "2. \"2x%2B5y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply the first equation by 5 and the second equation by 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3. \"5x-15y=55\"
\n" ); document.write( "4. \"6x%2B15y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add the equations, term-by-term:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5. \"11x%2B0y=55\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve
\n" ); document.write( "\"11x=55\"
\n" ); document.write( "\"x=5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And again, the solution set is the ordered pair (5,-2). I sincerely hope that you weren't surprised that we got the same answer with either method.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );