document.write( "Question 124242: Solve by substitution or elimination:
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document.write( "x=3y+11
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document.write( "2x+5y=0
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document.write( "I dont understand could I please have help for this question?
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Algebra.Com's Answer #91034 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitution: \n" ); document.write( "The first equation is already solved for x, so you can take the right-hand expression and substitute it for x into the second equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify and solve: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now that you have a value for y, you can substitute that back into either equation to solve for x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the solution set for this system is the ordered pair (5,-2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Elimination: \n" ); document.write( "Your second equation is in standard form ( \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1. \n" ); document.write( "2. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The idea is to multiply one or both of the equations by a constant or constants so that the coefficients on one of the variables will become additive inverses. In this case, multiplying the first equation by -2 will give you a -2x in the first equation and 2x in the second equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. \n" ); document.write( "2. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now add the two equations, term by term:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And solve:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you can do either of two things. One, you can substitute this value for y back into either of the original equations and solve for x. Or two, you can go back to the original equations, find a different multiplier or multipliers that will allow you to eliminate the y variable and solve for x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We've already done the first way as the second step of the substitution method, so let's try the second way:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1. \n" ); document.write( "2. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the first equation by 5 and the second equation by 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. \n" ); document.write( "4. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the equations, term-by-term:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And again, the solution set is the ordered pair (5,-2). I sincerely hope that you weren't surprised that we got the same answer with either method.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |